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When a charged particle moves on uniform magnetic field (B), it experience a force F as F= Bqv sinΘ, where q is charge particle, v be its velocity and Θ be is angle between B and v. This force is acting toward the motion of the circle or motion is circular. The direction of force F and distance coveRead more
When a charged particle moves on uniform magnetic field (B), it experience a force F as F= Bqv sinΘ, where q is charge particle, v be its velocity and Θ be is angle between B and v. This force is acting toward the motion of the circle or motion is circular. The direction of force F and distance covered s are always perpendicular to each other such that, work done W = FS cos90 = 0. so, the magnetic force does no work done but moves the particle in circular motion.
See lessGiven , Mass of object (m) = 1kg Length of string (l) = 4m Radius of circle (r) = 60cm Tension on the string (T) = ? Period of motion = ? From figure , Tsinθ = mv2/r Tcosθ =mg tanθ = v2/rg and sinθ = r/l = 0.6/1 = 0.6 or , θ = sin-1(0.6) = 36.87 so from relation Tcosθ =mg T = mg/cosθ =1x10/cos36.Read more
Given ,
Mass of object (m) = 1kg
Length of string (l) = 4m
Radius of circle (r) = 60cm
Tension on the string (T) = ?
Period of motion = ?
From figure ,
Tsinθ = mv2/r
Tcosθ =mg
tanθ = v2/rg and
sinθ = r/l = 0.6/1 = 0.6
or , θ = sin-1(0.6) = 36.87
so from relation
Tcosθ =mg
T = mg/cosθ =1×10/cos36.87 = 12.5 N
Again , from relation
tanθ = v2/rg
or , t = 2π√lcosθ/g
= 2π√1xcos36.87/10 = 1.78s
Given, Separation of plates (d) =25mm Mass of drop (m) =5x10-15kg Potential difference (V) =1000v Charge on the drop (q) =? if the oil drop remains stationary , then The force on oil drop due to electric field =weight of the drop i.e. qE=mg or ,q =mg/E =mg/v/d =mgd/v = 5x10-15x10x25x10-3/1Read more
Given,
Separation of plates (d) =25mm
Mass of drop (m) =5×10-15kg
Potential difference (V) =1000v
Charge on the drop (q) =?
if the oil drop remains stationary , then
The force on oil drop due to electric field =weight of the drop
i.e. qE=mg
or ,q =mg/E =mg/v/d =mgd/v
= 5×10-15x10x25x10-3/1000 =1.25×10-18c
∴The charge on the oil drop q =1.25×10-18c
Hence the required charge on the oil drop is 1.25×10-18c.
A big rock has large mass than smaller pebble . Thus , the big rock has greater change in momentum than the pebble . When we kick to large rock , the change in momentum i.e. the force exerted by large rock is greater than smaller pebble . Due to this reason , it can hurt our foot more to kick a bigRead more
A big rock has large mass than smaller pebble . Thus , the big rock has greater change in momentum than the pebble . When we kick to large rock , the change in momentum i.e. the force exerted by large rock is greater than smaller pebble . Due to this reason , it can hurt our foot more to kick a big rock than a small pebble .
See lessThe engine consist of fixed cylinder and a moving piston . The expanding combustion gases push the piston , which in turn rotates the crankshaft . After the piston compress the fuel air mixture , the sparks ignites it , causing combustion . The expansion of the combustion gases pushes the piston dRead more
The engine consist of fixed cylinder and a moving piston . The expanding combustion gases push the piston , which in turn rotates the crankshaft . After the piston compress the fuel air mixture , the sparks ignites it , causing combustion . The expansion of the combustion gases pushes the piston during power stroke.
An induced current is a current that is produced in a conductor when there is a change in the magnetic field surrounding it. Unlike a direct current (DC), which flows continuously in one direction, an induced current is alternating in nature and changes direction periodically. The direction of an inRead more
An induced current is a current that is produced in a conductor when there is a change in the magnetic field surrounding it. Unlike a direct current (DC), which flows continuously in one direction, an induced current is alternating in nature and changes direction periodically.
The direction of an induced current is not determined by the current itself but is instead determined by the direction of the changing magnetic field that is causing the current. According to Faraday’s law of electromagnetic induction, the magnitude and direction of an induced current are proportional to the rate of change of the magnetic field. The induced current will flow in a direction such that it opposes the change in the magnetic field that produced it, as described by Lenz’s law.
Therefore, the direction of the induced current is not determined by any intrinsic property of the current itself, but rather by the external factors that are causing it to be induced.