Option b is the correct answer!!! Explanation: v=√(T/m) v∝√T.
Option b is the correct answer!!!
Explanation: v=√(T/m)
v∝√T.
Know It Here Latest Questions
a) 1/√T b) √T c) T d) 1/T
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Given, Force (f) =0.1 N Distance between Charge (r) =540 cm Charge (q) =? we know that , F = 1/4π∈o.qxq/x2 ( air ) or , 0.1 =9x109xq2/(0.5)2 or , √0.1x0.25/9x109 = q or ,q =√0.025/9x109 =√0.000278x10-8 =√2.78x10-12 ∴ q =1.67x10-6 c In the second part , a medium of dielectric constanRead more
Given,
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Force (f) =0.1 N
Distance between Charge (r) =540 cm
Charge (q) =?
we know that ,
F = 1/4π∈o.qxq/x2 ( air )
or , 0.1 =9×109xq2/(0.5)2
or , √0.1×0.25/9×109 = q
or ,q =√0.025/9×109
=√0.000278×10-8
=√2.78×10-12
∴ q =1.67×10-6 c
In the second part , a medium of dielectric constant is placed i.e. k =10 , Distance (r) =?
F =1/4π∈ok .q2/r2
or , 0.1 =9×109/10 x(1.67×10-6)2/r2
or , r =√9×109x(1.67×10-6)2
or , r =√25.10×10-3
∴r =0.16 m
A. MAC Address Assignments B. Port Assignments to network devices C. Distribute IP address to network devices D. Routes to use for forwarding data to its destination
A. MAC Address Assignments
B. Port Assignments to network devices
C. Distribute IP address to network devices
D. Routes to use for forwarding data to its destination
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Routing tables of a router keeps track of Routes to use for forwarding data to its destination.
Routing tables of a router keeps track of Routes to use for forwarding data to its destination.
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A) Database B) Document Processor C) Graphic Package D) Spread Sheet
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Option D is the correct answer!!! Spread Sheet the following software applications would be the most appropriate for performing numerical and statistical calculations.
Option D is the correct answer!!!
Spread Sheet the following software applications would be the most appropriate for performing numerical and statistical calculations.
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A) the computer that terminates the data B) the computer that originates the data C) the computer that routes the data D) all of the mentioned
A) the computer that terminates the data
B) the computer that originates the data
C) the computer that routes the data
D) all of the mentioned
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Option D is the correct answer!!! In computer network nodes are i. the computer that terminates the data ii. the computer that originates the data iii. the computer that routes the data
Option D is the correct answer!!!
In computer network nodes are
i. the computer that terminates the data
ii. the computer that originates the data
iii. the computer that routes the data
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A) Tree B) Binary Tree C) Queue D) Graph
A) Tree
B) Binary Tree
C) Queue
D) Graph
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Given, Separation of plates (d) =25mm Mass of drop (m) =5x10-15kg Potential difference (V) =1000v Charge on the drop (q) =? if the oil drop remains stationary , then The force on oil drop due to electric field =weight of the drop i.e. qE=mg or ,q =mg/E =mg/v/d =mgd/v = 5x10-15x10x25x10-3/1Read more
Given,
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Separation of plates (d) =25mm
Mass of drop (m) =5×10-15kg
Potential difference (V) =1000v
Charge on the drop (q) =?
if the oil drop remains stationary , then
The force on oil drop due to electric field =weight of the drop
i.e. qE=mg
or ,q =mg/E =mg/v/d =mgd/v
= 5×10-15x10x25x10-3/1000 =1.25×10-18c
∴The charge on the oil drop q =1.25×10-18c
Hence the required charge on the oil drop is 1.25×10-18c.
A. FTP B. TCP C. UDP D. B & C
A. FTP
B. TCP
C. UDP
D. B & C
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In the very cold regions , the temperature of the air outside the room will be very low as compared the temperature inside the room. There is a large difference of temperature inside and outside th room because glass is a bad conductor of heat. Due to this reason, there is an unequal expansion the oRead more
In the very cold regions , the temperature of the air outside the room will be very low as compared the temperature inside the room. There is a large difference of temperature inside and outside th room because glass is a bad conductor of heat. Due to this reason, there is an unequal expansion the outer and inner sides of glass and hence, the glass windows cracks.
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A the third body which is uncharged contact with body A then both distribute net charge equally. e.g. Qnet=(0+qa) because they equally distribute so, both have finally qa/2 charge available. now third body contact with body B then Qnet=(qa/2+qb) now both distribute charge equally hence, each has (qaRead more
A the third body which is uncharged contact with body A then both distribute net charge equally.
e.g. Qnet=(0+qa)
because they equally distribute so, both have finally qa/2 charge available.
now third body contact with body B
then Qnet=(qa/2+qb)
now both distribute charge equally
hence,
each has (qa/2+qb)/2
hence finally charge in body A=qa/2
See lesscharge in body B=(qa/2+qb)/2=qa/4+qb/2