A charge oil drop remains stationary when situated between two parallel horizontal metal plates 25 mm apart and a p.d. of 1000v is applied to the plates . find the charge on the drop if it has mass of 5 x10^-15 kg.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Given,
Separation of plates (d) =25mm
Mass of drop (m) =5×10-15kg
Potential difference (V) =1000v
Charge on the drop (q) =?
if the oil drop remains stationary , then
The force on oil drop due to electric field =weight of the drop
i.e. qE=mg
or ,q =mg/E =mg/v/d =mgd/v
= 5×10-15x10x25x10-3/1000 =1.25×10-18c
∴The charge on the oil drop q =1.25×10-18c
Hence the required charge on the oil drop is 1.25×10-18c.